12.64a | In neutral solution, k = 2.1 × 10^−11 s−1 at 27 °C and 8.5 × 10^−11 s−1 at 37 °C. Determine
Why it's on BrighterTube
Hand-picked by a BrighterTube curator · found via BookPractice video map (Josh's list, Nov 4 · 90% confidenceWorked solution to exercise 12.64a in OpenStax Chemistry 2e (In neutral solution, k = 2.1 × 10^−11 s−1 at 27 °C and 8.5 × 10^−11 s−1 at 37 °C. Determine); BookPractice shows it as the video solution for that exact problem. Also mapped in 1 other book (OpenStax Chemistry: Atoms First 2e).
What you'll learn
A 27-minute chemistry worked example from The Glaser Tutoring Company, solving exercise 12.64a of OpenStax Chemistry 2e step by step.
Video by The Glaser Tutoring Company, played through YouTube's embedded player.