[a^k] = [a^gcd(n,k)] and |a^k| = n/gcd(n,k) Proof (Abstract Algebra)
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Hand-picked by a BrighterTube curator · found via round-3 back catalogue of a channel Lumen picks video by video · 82% confidenceProves two related results about powers in cyclic groups involving the gcd function. Descriptive title with formal notation matching the mathematical content.
A 12-minute video from BriTheMathGuy: “[a^k] = [a^gcd(n,k)] and |a^k| = n/gcd(n,k) Proof (Abstract Algebra)”.
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Part of Abstract Algebra